Which Of The Following Could Be The Function Graphed Correctly
12 Free tickets every month. Use your browser's back button to return to your test results. We'll look at some graphs, to find similarities and differences. Question 3 Not yet answered. Which of the following equations could express the relationship between f and g? Which of the following could be the function graph - Gauthmath. When you're graphing (or looking at a graph of) polynomials, it can help to already have an idea of what basic polynomial shapes look like. First, let's look at some polynomials of even degree (specifically, quadratics in the first row of pictures, and quartics in the second row) with positive and negative leading coefficients: Content Continues Below.
- Which of the following could be the function graphed based
- Which of the following could be the function graphed for a
- Which of the following could be the function graphed within
- Which of the following could be the function graphed by the function
Which Of The Following Could Be The Function Graphed Based
Since the sign on the leading coefficient is negative, the graph will be down on both ends. Graph D shows both ends passing through the top of the graphing box, just like a positive quadratic would. Which of the following could be the equation of the function graphed below? SAT Math Multiple-Choice Test 25. Which of the following could be the function graphed within. We see that the graph of first three functions do not match with the given graph, but the graph of the fourth function given by. The only equation that has this form is (B) f(x) = g(x + 2). Ask a live tutor for help now. These traits will be true for every even-degree polynomial.
Which Of The Following Could Be The Function Graphed For A
Thus, the correct option is. But If they start "up" and go "down", they're negative polynomials. High accurate tutors, shorter answering time. Therefore, the end-behavior for this polynomial will be: "Down" on the left and "up" on the right.
Which Of The Following Could Be The Function Graphed Within
Answer: The answer is. This polynomial is much too large for me to view in the standard screen on my graphing calculator, so either I can waste a lot of time fiddling with WINDOW options, or I can quickly use my knowledge of end behavior. Recall from Chapter 9, Lesson 3, that when the graph of y = g(x) is shifted to the left by k units, the equation of the new function is y = g(x + k). In all four of the graphs above, the ends of the graphed lines entered and left the same side of the picture. Get 5 free video unlocks on our app with code GOMOBILE. To check, we start plotting the functions one by one on a graph paper. Now let's look at some polynomials of odd degree (cubics in the first row of pictures, and quintics in the second row): As you can see above, odd-degree polynomials have ends that head off in opposite directions. Y = 4sinx+ 2 y =2sinx+4. Which of the following could be the function graphed based. Create an account to get free access. Enjoy live Q&A or pic answer. Gauthmath helper for Chrome. SAT Math Multiple Choice Question 749: Answer and Explanation. Try Numerade free for 7 days.
Which Of The Following Could Be The Function Graphed By The Function
If they start "down" (entering the graphing "box" through the "bottom") and go "up" (leaving the graphing "box" through the "top"), they're positive polynomials, just like every positive cubic you've ever graphed. The figure clearly shows that the function y = f(x) is similar in shape to the function y = g(x), but is shifted to the left by some positive distance. Enter your parent or guardian's email address: Already have an account? Which of the following could be the function graphed for a. Crop a question and search for answer. If you can remember the behavior for quadratics (that is, for parabolas), then you'll know the end-behavior for every even-degree polynomial.
One of the aspects of this is "end behavior", and it's pretty easy. Advanced Mathematics (function transformations) HARD. Unlimited answer cards. To answer this question, the important things for me to consider are the sign and the degree of the leading term. This problem has been solved!
The only graph with both ends down is: Graph B. To unlock all benefits!